A 20.0 kg box is dragged across a rough floor by a horizontalforce of 85.0N (i).

Question

A 20.0 kg box is dragged across a rough floor by a horizontalforce of 85.0N (i). Starting from rest, the force acts for3.00 s and the box is displaced 5.90 m in the +x direction. Determine the coefficient of friction between the box and thefloor. ANSWER: 0.30 A 20.0 kg box is dragged across a rough floor by a horizontalforce of 85.0N (i). Starting from rest, the force acts for3.00 s and the box is displaced 5.90 m in the +x direction. Determine the coefficient of friction between the box and thefloor. ANSWER: 0.30

Explanation / Answer

The box starts from rest so that acceleration of the boxis s =0.5at2         ==> a = 2s /t2                   = 2 * 5.90 / 9                    = 1.311 m/s2 The force acting on the box         F = 85.0 - f ==> ma = 85 - mg ==>   20 * 1.311 = 85 - 20 * 9.8 ==> = 0.2998 ˜ 0.30

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.