A 150 g block is launched along a horizontal surface with the350 N force provide

Question

A 150 g block is launched along a horizontal surface with the350 N force provided by a spring initially compressed 4.50 cm. After sliding along asmooth surface, the block enters a region with a rough surface of length d = 17:0 m and exits theregion at speed of 4.00 m/s. What is the coecient of kinetic friction of the rough surface?answer: 0.267 A 150 g block is launched along a horizontal surface with the350 N force provided by a spring initially compressed 4.50 cm. After sliding along asmooth surface, the block enters a region with a rough surface of length d = 17:0 m and exits theregion at speed of 4.00 m/s. What is the coecient of kinetic friction of the rough surface?answer: 0.267

Explanation / Answer

Work done by the spring A=kx^2/2 while kx=F=350N. so A=kx^2/2=F*x/2. work done by the spring change to kinetic energy of the mass. F*x/2=mv^2/2 so Fx=mv^2. so v=sqrt(Fx/m)=10,25(m/s). ------ let the coefficient of kinetic friction be . a=-g. so -2**g*L=4^2-10,25^2. so =0,267

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