What is thecomponent of the gravitational force along the bedding plane? Whatis

Question

What is thecomponent of the gravitational force along the bedding plane? Whatis the component perpendicular to the plane? What is the normalforce? What is the maximum possible value of the static frictionalforce? The figure below shows the cross section of a road cut into theside of a mountain. The solid line AA' represents a weakbedding plane along which sliding is possible. Block Bdirectly above the high way is separated from uphill rock by alarge crack (called a joint), so that only frictionbetween the block and the bedding plane prevents sliding. The massof the block is 1.2 multiplied by 107 kg,the dip angle ? of the bedding plane is 27, and the coeffient ofstatic friction between block and plane is 0.63. (a) Show that the block will not slide. 1 (b) Water seeps into the joint and expands upon freezing, exertingon the block a force F parallel to AA'. Whatminimum value of F will trigger a slide? 2Your answer is correct. N What is thecomponent of the gravitational force along the bedding plane? Whatis the component perpendicular to the plane? What is the normalforce? What is the maximum possible value of the static frictionalforce?

Explanation / Answer

F(along the bedding plane) = mgsin = 1.2*107* 9.8* sin27 = 5.34*107N F(perpendicular) = mgcos = 1.2*107 *9.8*cos27 = 1.048 *108N The normal force is the same as the perpendicular force justdirected upwards from the surface Ff = Fn = mgcos = 0.63* 1.2*107 * 9.8*cos27 = 6.60*107N Hope that helps

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