The front of a 1,500 kg car is designed as a \"crumple zone\"that collapses to a

Question

The front of a 1,500 kg car is designed as a "crumple zone"that collapses to absorb the shock of a collision. If a cartravelling 35.0 m/s stops uniformly in 1.65 m,

a) how long does the collision last?
b) what is the magnitude of the average force
c) what is the acceleration of the car? Express your answeras a multiple of the accleration of gravity. (For example,"2g".)


a) how long does the collision last? b) what is the magnitude of the average force
c) what is the acceleration of the car? Express your answeras a multiple of the accleration of gravity. (For example,"2g".)

Explanation / Answer

The mass of the car m = 1500 kg The speed of the car u = 35 m/s The final speed of the car v = 0 m/s The distance traveled s = 1.65 m The acceleration of the car is            v2 - u2 = 2 a s                   a = - u2 / 2 s = - 35 * 35 / 2 * 1.65  = - 371.21 m/s2 a) u = - at     ==. t = - u / a = - 35 / -371.21 =0.0942 s b) F = ma     F=1500 * 371.2        = 556800 N c) a = -371.21 m/s2 = 37.87 g

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