a man pushes a lawn mower on a level lawn with a force of212N. If 52% of this is

Question

a man pushes a lawn mower on a level lawn with a force of212N. If 52% of this is directed downward, how much work is done bythe man in pushing the mower 4.8 m.______J a)what is the kinetic energy in joules of a 1060-kg automobiletraveling at 94 km/h._______J b)how much work would have to be done to bring a 1060-kgautomobile traveling at 94 km/h to a stop.______________J a man pushes a lawn mower on a level lawn with a force of212N. If 52% of this is directed downward, how much work is done bythe man in pushing the mower 4.8 m.______J a)what is the kinetic energy in joules of a 1060-kg automobiletraveling at 94 km/h._______J b)how much work would have to be done to bring a 1060-kgautomobile traveling at 94 km/h to a stop.______________J

Explanation / Answer

Force F = 212 N

Down ward force F ‘ = 52 % of F = 0.52 F= 110.24N

                      F sin = 110.24

                                 = 31.33 degrees

Horizontal force F “ = F cos 31.33

                                = 181 N

(a). distance S= 4.8 m

So, work done W = F “ S

                             = 869.2 J

(b). Mass m = 1060 kg

Speed v = 94 km/ h= 94 * ( 5/ 18) m / s

                                = 26.111 m / s

Work done = change in kinetic energy

                  = ( 1/ 2) mv ^ 2   Since final speed =0

                   = 361348.76 J

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