Q#3 (a)Agardener pushes a box of tools across a drivway byapplying 32.5N of forc

Question

Q#3 (a)Agardener pushes a box of tools across a drivway byapplying 32.5N of force downwards at an angle of 22.4 degrees withrespect to the horizontal. how much work is done mopving thebox2.254 m in the horizontal direction? (b) (a) How much work is needed to push a 132kg packingcrate a distance of 2.65m up a fricktionless incline plain thatmake an angle of 20.0 degrees with the horizontal?(b) how much workwould be required to move the crate the same distance if theincline plain had a coefficient of friction of 0.20? (c) A 50.0 kg gymnast stretches a vertical spring by 0.5 mwhen she hangs from it. How much energy is stored in thespring? (d) A 2.5 gram ping-pong ball at rest is set in motion by theuse of 1.8 J of energy. if all the energy goes into the motionof the ball, what is the ball's maximum speed? Q#3 (a)Agardener pushes a box of tools across a drivway byapplying 32.5N of force downwards at an angle of 22.4 degrees withrespect to the horizontal. how much work is done mopving thebox2.254 m in the horizontal direction? (b) (a) How much work is needed to push a 132kg packingcrate a distance of 2.65m up a fricktionless incline plain thatmake an angle of 20.0 degrees with the horizontal?(b) how much workwould be required to move the crate the same distance if theincline plain had a coefficient of friction of 0.20? (c) A 50.0 kg gymnast stretches a vertical spring by 0.5 mwhen she hangs from it. How much energy is stored in thespring? (d) A 2.5 gram ping-pong ball at rest is set in motion by theuse of 1.8 J of energy. if all the energy goes into the motionof the ball, what is the ball's maximum speed?

Explanation / Answer

a) W = F d = 32.5 * cos 22.5 * 2.254 = 67.7J       horizontal force *distance
b) (1)    h = 2.65 * sin 20 = .906m    height to which crate rises              W = m g h = 132 * 9.8 * .906 = 1172 J       (2)  Wf= N d = .2 * m g cos 20 * d = .2 * 132 * 9.8 *.940 * 2.65 = 644 J     work done againstfriction             Total work = 1172 + 644 = 1816 J c) PE = m g h = 50 * 9.8 * .5 = 245 J d) 1/2 m v2 = 1.8       v = (2 * 1.8 / .0025) =1440 m/s

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