Q#3 A 3.0 kg ball has a velocity of 25 m/s downward just before it strike the gr

Question

Q#3 A 3.0 kg ball has a velocity of 25 m/s downward just before it strike the ground and bounces up with a velocity of25 m/s upward, (a) what is the change in momentum(impulse)  of the ball?. (b) If the ball is in contactwith the ground for 0.20 s, what is the average force experiencedby the ball on impact with the groung? Q#3 A 3.0 kg ball has a velocity of 25 m/s downward just before it strike the ground and bounces up with a velocity of25 m/s upward, (a) what is the change in momentum(impulse)  of the ball?. (b) If the ball is in contactwith the ground for 0.20 s, what is the average force experiencedby the ball on impact with the groung?

Explanation / Answer

(a) change in momentum = final mv   -   initial mv = m (final v -initial v) = .           = 3.0 ( 25 -   -25) =     150N-s . (b) change in momentum = avg force *time .        150 N-s = F * 0.20 s .    F = 750 N

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