An object that is 29 cm in front of a convex mirror has animage located 21 cm be

Question

An object that is 29 cm in front of a convex mirror has animage located 21 cm behind the mirror. How far behind the mirror isthe image located when the object is 9.2 cm in front of themirror?

I'm sure im making this soo much harder than it is .... I've been using 1/V'= 1/-V + 1/U - 1/ U' and wheni plug everything in i get -8.208 which is not the answer soplease show me where I'm going wrong An object that is 29 cm in front of a convex mirror has animage located 21 cm behind the mirror. How far behind the mirror isthe image located when the object is 9.2 cm in front of themirror?

I'm sure im making this soo much harder than it is .... I've been using 1/V'= 1/-V + 1/U - 1/ U' and wheni plug everything in i get -8.208 which is not the answer soplease show me where I'm going wrong

Explanation / Answer

The focal length of the mirror is       1 / f   = 1 / o + 1 / i                = 1 / 29   - 1 / 21 ==> f = - 76.12 cm Therefore       - 1 / 76.12   = 1 / 9.2 + 1 / i     ==> 1 / i = 1 / 9.2 - 1 /76.12     ==> i = 10.46 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.