IP An object is located to the left of aconvex lens whose focal length is 38 cm.
ID: 1672900 • Letter: I
Question
IP An object is located to the left of aconvex lens whose focal length is 38 cm. The magnification producedby the lens is m1 = 2.6. To increase the magnification to 3.8,should the object be moved closer to the lens or fartheraway? Calculate the distance through whichthe object should be moved. do=_______cm IP An object is located to the left of aconvex lens whose focal length is 38 cm. The magnification producedby the lens is m1 = 2.6. To increase the magnification to 3.8,should the object be moved closer to the lens or fartheraway? Calculate the distance through whichthe object should be moved. do=_______cm Calculate the distance through whichthe object should be moved. do=_______cm Calculate the distance through whichthe object should be moved. do=_______cmExplanation / Answer
given focal length f = 38 cm magnification m = 2.6 let di and do are the image and object distance then we have m = - di /do so di = - 2.6 do from the thin lence equation 1/f = 1/di +1/do 1/38 = -1/ 2.6do + 1/ do do = 23.3846 cm to get the greater magnified image the object should bemoved away from the lens substitute the value of di and f and calculate forthe value of do again calculate the value of do by taking m = 3.8 then we have m = - di /do so di = - 3.8 do so di = - 3.8 do 1/f = 1/di +1/do 1/38 = -1/ 3.8do + 1/ do do = 28 cm 1/38 = -1/ 3.8do + 1/ do do = 28 cm then the difference of the first and second do is therequired answer the differecne is = 28 - 23.3846 = 4.6154cmRelated Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.