A hockey puck is hit on a frozen lake and startsmoving with a speed of 13 m/s. E
ID: 1673260 • Letter: A
Question
A hockey puck is hit on a frozen lake and startsmoving with a speed of 13 m/s. Exactly5.00 s later, its speed is 4.1 m/s What is its average acceleration?What is the average value of the coefficient of kinetic frictionbetween puck and ice?
How far does the puck travel during this 5.00 s interval?
A hockey puck is hit on a frozen lake and startsmoving with a speed of 13 m/s. Exactly5.00 s later, its speed is 4.1 m/s What is its average acceleration?
What is the average value of the coefficient of kinetic frictionbetween puck and ice?
How far does the puck travel during this 5.00 s interval?
Explanation / Answer
We will use basic kinematics for this problem: avg acceleration = v2 - v1/t2 - t1 Avg acc. = 4.1 - 13/ 5 - 0 = -1.78 m/s2 Now for the coefficent: F=ma the only force acting in the x direction is the force dueto friction mg = ma the masses cancel out and you get: = a/g = .18 Now for the distance traveled Vavg = V1 + V2 / 2 Vavg = 8.55 m/s distance traveled = velocity x time 8.55 x 5 = 42.75 m Cheers Billy Now for the coefficent: F=ma the only force acting in the x direction is the force dueto friction mg = ma the masses cancel out and you get: = a/g = .18 Now for the distance traveled Vavg = V1 + V2 / 2 Vavg = 8.55 m/s distance traveled = velocity x time 8.55 x 5 = 42.75 m Cheers BillyRelated Questions
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