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In an oscillating LC circuit with C =67.0 µF, the current as afunction of time i

ID: 1673479 • Letter: I

Question

In an oscillating LC circuit with C =67.0 µF, the current as afunction of time is given by I = (1.70) sin(2700t + 0.620), where t is in seconds, Iin amperes, and the phase angle in radians. (a) How soon after t = 0 will thecurrent reach its maximum value?
1 s

(b) What is the inductance L?
2 H

(c) What is the total energy?
3 J
(a) How soon after t = 0 will thecurrent reach its maximum value?
1 s

(b) What is the inductance L?
2 H

(c) What is the total energy?
3 J

Explanation / Answer

    first we compare the given equation with     i = I sin(t + o)setting     (t + ) = (2700 t + 0.620)     obtaining t = ......... s (a)     as = 2700 rad / s            = (L C)-1/2     L = 1 / 2 C         = ......... H (b)     the energy stored will be     U = (1 / 2) L i2

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