1) (a) An electron and a proton are eachaccelerated from rest in a uniform elect
ID: 1673576 • Letter: 1
Question
1) (a) An electron and a proton are eachaccelerated from rest in a uniform electric field of 2.0 ×105 V/m. What are their kinetic energies inJoules after they have each traveled a distance of 0.20 m in theelectric field?(b) What is the ratio of the speeds of theelectron and proton after they have each traveled a distance of0.20 m in the electric field? 2) (a) A 2.0 F capacitor with aninitial charge Q is discharged through a500 kresistor. How much time is required for the charge on the capacitorto decrease to Q/2? (b) What is the current at the instant whenthe discharging begins? 1) (a) An electron and a proton are eachaccelerated from rest in a uniform electric field of 2.0 ×105 V/m. What are their kinetic energies inJoules after they have each traveled a distance of 0.20 m in theelectric field?
(b) What is the ratio of the speeds of theelectron and proton after they have each traveled a distance of0.20 m in the electric field? 2) (a) A 2.0 F capacitor with aninitial charge Q is discharged through a500 kresistor. How much time is required for the charge on the capacitorto decrease to Q/2? (b) What is the current at the instant whenthe discharging begins?
Explanation / Answer
1) their kinetic energies in Joules after they have eachtraveled a distance of 0.20 m in the electric field E=F*distance=2.0 × 105 *1.6*10-19*0.2=6.4*10-15J (b)the ratio of the speeds of the electron and proton afterthey have each traveled a distance of 0.20 m in the electricfield me*ve2/2=mp*vp2/2 => ve/vp=mp/me=42.84 me=9.1*10-31 kg mp=1.67*10-27 kg me=9.1*10-31 kg mp=1.67*10-27 kg (2)time required time constant=T=RC Q/2=Q*exp{-t/T} =>t=ln2*T=0.693 s =>t=ln2*T=0.693 s (b)the current at the instant when the dischargingbegins I=Q/CR if count on direction I=-Q/CR if count on direction I=-Q/CR Q is initial charge on the capacitorRelated Questions
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