In a setup like that in Figure 27.7, a wavelength of 625 nm isused in a Young’s

ID: 1673735 • Letter: I

Question

In a setup like that in Figure 27.7, a wavelength of 625 nm isused in a Young’s double-slit experiment. The separationbetween the slits is d = 1.4 x 10-5 m. Thetotal width of the screen is 0.20 m. In one version of the setup,the separation between the double slit and the screen isLA = 0.21 m, whereas in another version it isLB = 0.23 m. On one side of the central brightfringe, how many bright fringes lie on the screen in the twoversions of the setup? Do not include the central bright fringe inyour counting.

Explanation / Answer

Position of a bright fringe is given by : y = D/d when y=0 is at the central bright fringe. So, Yn = nD/d, n being the farthest bright fringe on one sideof the central maximum. So, 0.20/2 = n*D*(6.25*10-7)/(1.4*10-5) =0.10 m So, total no. of bright fringes is 2n. In the first case, La = D = 0.21m So, n = 10 For Lb = D = 0.23 m, n = 9

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In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young’s

In a setup like that in Figure 27.7, a wavelength of 625 nm isused in a Young’s

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In a setup like that in Figure 27.7, a wavelength of 625 nm isused in a Young’s

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