Red light of wavelength 633 nm ( nm = 10 9 m )from a neon gas discharge tube in

Question

Red light of wavelength 633 nm ( nm = 109 m )from a neon gas discharge tube in air (n = 1.0 ) passes into a block of glass at an incident angle of 42°and slows down to 1.86 x 108 m/s. Calculate the                                                                  (c = 3.0 x 108 m/s ) a) Refracted angle in the glass. b)Critical angle for the glass. c) Wavelength and frequency of the light in the glass. Red light of wavelength 633 nm ( nm = 109 m )from a neon gas discharge tube in air (n = 1.0 ) passes into a block of glass at an incident angle of 42°and slows down to 1.86 x 108 m/s. Calculate the                                                                  (c = 3.0 x 108 m/s ) a) Refracted angle in the glass. b)Critical angle for the glass. c) Wavelength and frequency of the light in the glass.

Explanation / Answer

index of refraction is    n = c /v = 3.00 / 1.86 =    1.613 . (a) to get refractedangle           sin42 = nsin         where is refracted angle .         sin42 = 1.613sin            =  24.51 degrees . (b) critical angle is found by setting incident angleequal to 90 and solve for refracted angle .           sin90 = n sin .           1 = 1.613 sin         =   38.32 degrees . (c) wavelength = orginal wavelength /n = 633 / 1.613 =    392.5nm .        freq = speed/ wavelength =   1.86 x 108 / 392.5 x10-9 =   4.739 x 1014 Hz

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