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What is the wavelength of (a) a photon withenergy 6.0 eV (in nm), (b) an electro

ID: 1674707 • Letter: W

Question

What is the wavelength of (a) a photon withenergy 6.0 eV (in nm), (b) an electron with energy6.0 eV (in nm), (c) a photon of energy 6.0 GeV (infm), and (d) an electron with energy 6.0 GeV (infm)?

(a)

Number

Units

(b)

Number

Units

(c)

Number

Units

(d)

Number

Units

Chapter 38, Problem 45 Chapter 38, Problem 45 Incorrect. What is the wavelength of (a) a photon withenergy 6.0 eV (in nm), (b) an electron with energy6.0 eV (in nm), (c) a photon of energy 6.0 GeV (infm), and (d) an electron with energy 6.0 GeV (infm)? (a) Number 207 Units nm (b) Number 0.5012 Units nm (c) Number Units fm (d) Number Units fm

Explanation / Answer

   a.   Wavelength ofphoton      =   h* c / E          where Eis the energy of photon in joules.    E   =   6.0eV          =   6.0* 1.6 * 10-19          =   9.6* 10-19   J       6eV   =   6.62* 10-34 * 3.0 * 108 / 9.6 * 10-19                =   2.07* 10-7   m                =   207  nm                =   2.07* 10-7   m                =   207  nm    b.   For a movingparticle         =   h/ p                                                     =   h/ (2 * m * E)             6eV   =   6.62* 10-34 / (2 * 9.1 * 10-31 * 9.6 *10-19)                      =   5.001* 10-10      m                      =   0.5001   nm          =   6.0* 1.6 * 10-10          =   9.6* 10-10   J       6eV   =   6.62* 10-34 * 3.0 * 108 / 9.6 * 10-10                =   2.07* 10-16   m                =   0.207  fm                =   2.07* 10-16   m                =   0.207  fm    b.   For a movingparticle         =   h/ p                                                     =   h/ (2 * m * E)             6eV   =   6.62* 10-34 / (2 * 9.1 * 10-31 * 9.6 *10-10)                      =   1.584* 10-14      m                      =   15.84   fm
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