What is the wavelength of (a) a photon with energy 1.00eV, (b) an electron with

Question

What is the wavelength of (a) a photon with energy 1.00eV, (b) an electron with energy 1.00 eV, (c) a photon of energy1.00 GeV, and (d) an electron with energy 1.00 GeV? I am confused how to solve Part (d). Part (b) and (d) ask the same question...to find thewavelength of an electron with a given energy...but why isPart (d) solved differently from Part (b)? Equation E=p^2/2m is used in (b) to find momentum p,which is then plugged into lambda=h/p. However, Part (d)uses only E=hc/lambda to solve for wavelength. Why isthat? Does the magnitude of the particles energy changewhich equation is used to solve for wavelength? Thanks for your help. What is the wavelength of (a) a photon with energy 1.00eV, (b) an electron with energy 1.00 eV, (c) a photon of energy1.00 GeV, and (d) an electron with energy 1.00 GeV? I am confused how to solve Part (d). Part (b) and (d) ask the same question...to find thewavelength of an electron with a given energy...but why isPart (d) solved differently from Part (b)? Equation E=p^2/2m is used in (b) to find momentum p,which is then plugged into lambda=h/p. However, Part (d)uses only E=hc/lambda to solve for wavelength. Why isthat? Does the magnitude of the particles energy changewhich equation is used to solve for wavelength? Thanks for your help.

Explanation / Answer

de Broglie explained that lighthas both wave(reflection , refraction , Interference etc) and particle nature (Compton's effect). When light travells in the form of a wave then energy is:                        E   = hf          Where f   =   frequency of thewave.                             = h c / When it behavious as particle energy is :                       E   = 1/2 m v2                             =  P2 /2m                  Where P = momentum =   m * v(velocity) In problem if Momentum is to be calculated and energy isgiven we should use above formula. de Broglie wave length is :                           =   h / mv                             = h / P          Where (wave length ) represents the wave nature                     P(momentum) represents the particle nature. Hope this helps u!

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.