Protons are released from rest in a Van de Graaff acceleratorsystem. The protons
ID: 1674833 • Letter: P
Question
Protons are released from rest in a Van de Graaff acceleratorsystem. The protons initially are located where the electricpotential has a value of 6.10 MV and thenthey travel through a vacuum to a region where the potential iszero. (a) Find the final speed of these protons.1 m/s
(b) Find the accelerating electric field strength if the potentialchanged uniformly over a distance of 2.30 m.
2 MV/m (a) Find the final speed of these protons.
1 m/s
(b) Find the accelerating electric field strength if the potentialchanged uniformly over a distance of 2.30 m.
2 MV/m
Explanation / Answer
V = 6.10 MV, d = 2.30 m a) q*V = mv2/2 v = (2q*V/m) = 3.42*107 m/s b) E = V/d = 2.65 MV/m
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