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Protons are released from rest in a Van de Graaff acceleratorsystem. The protons

ID: 1674833 • Letter: P

Question

Protons are released from rest in a Van de Graaff acceleratorsystem. The protons initially are located where the electricpotential has a value of 6.10 MV and thenthey travel through a vacuum to a region where the potential iszero. (a) Find the final speed of these protons.
1 m/s

(b) Find the accelerating electric field strength if the potentialchanged uniformly over a distance of 2.30 m.
2 MV/m (a) Find the final speed of these protons.
1 m/s

(b) Find the accelerating electric field strength if the potentialchanged uniformly over a distance of 2.30 m.
2 MV/m

Explanation / Answer

V = 6.10 MV, d = 2.30 m a) q*V = mv2/2 v = (2q*V/m) = 3.42*107 m/s b) E = V/d = 2.65 MV/m

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