What is the tangential acceleration of a bug on the rim of a10-inch diameter dis
ID: 1675346 • Letter: W
Question
What is the tangential acceleration of a bug on the rim of a10-inch diameter disk if the disk moves from rest to an angularspeed of 99 rev/min in 3.0 s?A.) When the bug in the previous problem is at his final speedof 99 rev/s, what is the tangential velocity of the bug?
B.) One second after the bug starts from rest, what is thetangential acceleration of the bug?
C) One second after the bug starts from rest, what is itscentripetal acceleration? D) One second after the bug starts from rest, what is itsTOTAL acceleration? What is the tangential acceleration of a bug on the rim of a10-inch diameter disk if the disk moves from rest to an angularspeed of 99 rev/min in 3.0 s?
A.) When the bug in the previous problem is at his final speedof 99 rev/s, what is the tangential velocity of the bug?
B.) One second after the bug starts from rest, what is thetangential acceleration of the bug?
C) One second after the bug starts from rest, what is itscentripetal acceleration? D) One second after the bug starts from rest, what is itsTOTAL acceleration?
Explanation / Answer
The angular acceleration is the final angular velcoty minusthe initial angular velocity all divided by the time. So, intial angular velocty is 0rad/sec Final is 99(2rad/rev)/(60s)=about 10.367rad/sec time is 3 seconds, so angular acceleration is(10.367-0)/3=3.456rad/s2 Multiply by radius (5 in.) to get17.279in/s2 A)tangential velocity is angular velocity multiplied bythe radius, so 99rad*5in/s= 495 in/sec I don't knwo if the rest of the problems apply to the firstpart or the second part. I don't knwo if the rest of the problems apply to the firstpart or the second part.Related Questions
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