A converging lens ( f 1 = 24.0 cm) is located56.0 cm to the left of a diverging

Question

A converging lens (f1 = 24.0 cm) is located56.0 cm to the left of a diverging lens (f2 =28.0 cm). An object is placed to the left of the converginglens, and the final image produced by the two-lens combination lies19.4 cm to the left of the diverging lens.How far is the object from the converging lens? do1 = Thanks!!!!!!!!!!!! do1 = Thanks!!!!!!!!!!!! do1 =

Explanation / Answer

with respect to the diverging lens v=-19.4cm f=-28cm so u=? using the equation 1/v-1/u=1/f -1/u=1/-f -1/-v=-1/28+1/19.4=>u=-63.16cm with respect to the converging lens v=63.16cm f=24cm so u=? using the equation 1/v-1/u=1/f -1/u=1/f -1/v=1/24-1/63.16=>u=-38.70cm hence the object is at 38.70cm frm the converging lens.

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