In an American football game, a 89.3kg fullback running east with a speed of 5.0

Question

In an American football game, a 89.3kg fullback running east with a speed of 5.07 m/s is tackled by a 95.9 kg opponent running north with a speed of2.99 m/s. (a) If the collision is perfectly inelastic,calculate the speed and direction of the players just after thetackle.
1 m/s
2° (north of east)

(b) Determine the mechanical energy lost as a result of thecollision.
3 J
Account for the missing energy.
4 (a) If the collision is perfectly inelastic,calculate the speed and direction of the players just after thetackle.
1 m/s
2° (north of east)

(b) Determine the mechanical energy lost as a result of thecollision.
3 J
Account for the missing energy.
4

Explanation / Answer

east momentum is conserved so .    final east velocity = 89.3 * 5.07 / (89.3 + 95.9) =   2.44466 m/s .    final north velocity =   95.9 *2.99 / (89.3 + 95.9) =   1.5483 m/s . Total final velocity = (2.444662 + 1.54832 )1/2 =    2.894m/s . and an angle of    arctan(1.5483 /2.44466) =    32.35 degrees northof east . initial KE = (1/2) * 89.3 *5.072 + (1/2) * 95.9 *2.992   =    1576.4 Joules . final KE = (1/2) * 185.2 * 2.8942 =    775.4 Joules .     mech energy lost =   1576.4- 775.4   =     801.0 Joules . Energy was absorbed bythe bodies of the players when they hit. The energy was transformedinto heat.

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