In alcohol fermentation yeast converts glucose to ethanol and carbon dioxide: C_

Question

In alcohol fermentation yeast converts glucose to ethanol and carbon dioxide: C_6 H_12 O_6 (s) rightarrow 2C_2 H_5 OH(I) + 2CO_2 (g) If 5.97 g of glucose reacts and 1.44 L of CO_2 gas is collected at 293 K and 0.984 atm, what was the percent yield of the reaction? Dissolving 3.00 g of an impure sample of calcium carbonate in hydrochloric acid produced 0.656 L of carbon dioxide (@ 20.0 degree C and 792 mmHg). Calculate the percent by mass of calcium carbonate in the sample. [Assume no other in by mass component the sample produces carbon dioxide]. The empirical formula of a compound is CH. At 200.0 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm. What is the molecular formula of the compound?

Explanation / Answer

Question 6.

m = 5.97 g of glucose

MW of glucose = 180 g/mol

mol =mass/MW = 5.97/180 = 0.033166 mol

then

ratio is 1 mol of glucose = 2 mol of CO2

0.033166 mol --> 0.033166*2 =0.066332 mol of CO2 are epxected

calculate yield:

PV = nRT

n = PV/(RT) = (0.984)(1.44)/(0.082*293) = 0.0589761 moles recovered

the overall % yield

% yied = real / theoretical * !00% = 0.0589761 / 0.066332 *100 = 88.9104%

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.