Container A holds an ideal gas at a pressure of 5.0 x 10^5 Paand a temperature o

Question

Container A holds an ideal gas at a pressure of 5.0 x 10^5 Paand a temperature of 300K. It is connected by a thin tube (and aclosed valve) to container B, with 4 times the volume of A.Container B holds the same ideal gas at a preasure of 1.0 x 10^5 Paand a temperature of 400K. The valve is opened to allow thepressures to equalize, but the temp of each container ismaintained. What then is the pressure in the two containers? Container A holds an ideal gas at a pressure of 5.0 x 10^5 Paand a temperature of 300K. It is connected by a thin tube (and aclosed valve) to container B, with 4 times the volume of A.Container B holds the same ideal gas at a preasure of 1.0 x 10^5 Paand a temperature of 400K. The valve is opened to allow thepressures to equalize, but the temp of each container ismaintained. What then is the pressure in the two containers?

Explanation / Answer

P1 = 5.0*105 Pa, T1 = 300K. P2 = 1.0*105 Pa, T2 = 400 K.V2 = 4V1 Find the pressure in the two containers P use PV = nRT the total n is unchanged P1V1/RT1 +P2V2/RT2 =PV1/RT1 + PV2/RT2 P1V1/T1 +P2(4V1)/T2 =PV1/T1 + P(4V1)/T2 P1/T1 + 4P2/T2 =P/T1 + 4P/T2 P = (P1/T1 +4P2/T2)/(1/T1 + 4/T2) =2.0*105 Pa

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