The drawing shows three energy levels of a laser that areinvolved in the lasing
ID: 1676518 • Letter: T
Question
The drawing shows three energy levels of a laser that areinvolved in the lasing action. These levels are analogous to thelevels in the Ne atoms of a He-Ne laser. The E2level is a metastable level, and the E0 levelis the ground state. The difference between the energy levels ofthe laser is shown in the drawing. (a) What energy(in eV per electron) must an external source provide to start thelasing action? (b) What is the wavelength of thelaser light? (c) In what region of theelectromagnetic spectrum does the laser light lie (see Section24.2)?
(a) E = eV per electron (b) = (c)Explanation / Answer
a) the initial energy is the difference from the metastable levelto the ground state. b)Convert the answer from question a) into joules (1 eV = 1.6e-19Joules), then use the formula E=(h*c/lambda) where h=6.626e-34, c= 3e8 and E= the energy frompart a) isolate lambda (i.e. wavelength measured in meters) and this isyour wavelength of emitted light c) Compare your wavelength with the chart in section 24.2, or lookit up online, to determine which region it falls in
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