An object with a height of 2.31cm is placed 37.7mm to the left of a lens with a

Question

An object with a height of 2.31cm is placed 37.7mm to the left of a lens with a focal length of 35.4mm. Where is the image located? .58 (answer) Got it. Where is the image located? On the right of the lens (answer)Got it. ***What is the height of the image? The last one is the only one i can not figure out. I have usedm = Di/Do = Hi/Ho and ---->   Hi = -(Di/Do)*Ho I keep getting the wrong answer and have two attempts left.Any help would be pretty great. Thanks. An object with a height of 2.31cm is placed 37.7mm to the left of a lens with a focal length of 35.4mm. Where is the image located? .58 (answer) Got it. Where is the image located? On the right of the lens (answer)Got it. ***What is the height of the image? The last one is the only one i can not figure out. I have usedm = Di/Do = Hi/Ho and ---->   Hi = -(Di/Do)*Ho I keep getting the wrong answer and have two attempts left.Any help would be pretty great. Thanks.

Explanation / Answer

. Problem statement: An object with a height of 2.31cm is placed 37.7mm to the left of a lens with a focal length of 35.4mm. Where is the image located? .58 (answer) Got it. Where is the image located? On the right of the lens (answer)Got it. What is the height of the image? The last one is the only one i can not figure out. I have usedm = Di/Do = Hi/Ho and ---->   Hi = -(Di/Do)*Ho I keep getting the wrong answer and have two attempts left.Any help would be pretty great. Thanks. . 01.   1/f = 1/p + 1/q 02.   f = focal length (negative for divergingmirror or lens) 03.   p = distance between lens and object 04.   q = distance between lens and image 05.   m = q/p = (height of image)/(height ofobject) . 06.   q = [(1)/(35.4 mm) - (1)/(37.7mm)](-1) = 580.25mm 07.   q > 0    imageis on the opposite side of the lens from the object, i.e.,RHS 07.   m = q/p = (580.25 mm)/(37.7 mm) = 15.391 08.   (height of image) = (m)*(height of object) =(15.391)*(2.31 cm) = 35.554cm . Problem statement: An object with a height of 2.31cm is placed 37.7mm to the left of a lens with a focal length of 35.4mm. Where is the image located? .58 (answer) Got it. Where is the image located? On the right of the lens (answer)Got it. What is the height of the image? The last one is the only one i can not figure out. I have usedm = Di/Do = Hi/Ho and ---->   Hi = -(Di/Do)*Ho I keep getting the wrong answer and have two attempts left.Any help would be pretty great. Thanks. . 01.   1/f = 1/p + 1/q 02.   f = focal length (negative for divergingmirror or lens) 03.   p = distance between lens and object 04.   q = distance between lens and image 05.   m = q/p = (height of image)/(height ofobject) . 06.   q = [(1)/(35.4 mm) - (1)/(37.7mm)](-1) = 580.25mm 07.   q > 0    imageis on the opposite side of the lens from the object, i.e.,RHS 07.   m = q/p = (580.25 mm)/(37.7 mm) = 15.391 08.   (height of image) = (m)*(height of object) =(15.391)*(2.31 cm) = 35.554cm .

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