A bowling ball weighing 46.5 Ninitially moves at a speed of 4.30 m/s.How long mu
ID: 1677139 • Letter: A
Question
A bowling ball weighing 46.5 Ninitially moves at a speed of 4.30 m/s.How long must a force of 40.5 N be appliedto the ball to stop it?1 s Find the ball's change in momentum. Take theeast direction as the positive direction. 1 kg · m/s A boy of mass 50.1 kg is initially ona skateboard of mass 2.00 kg, moving at a speed of 9.8 m/s. The boy falls off the skateboard, and hiscenter of mass moves forward at a speed of 11.1 m/s. Find the final velocity of theskateboard.
magnitude 1 m/s direction 2---Select---forwardbackward magnitude 1 m/s direction 2---Select---forwardbackward
Explanation / Answer
A bowling ball weighing 46.5 N initiallymoves at a speed of 4.30 m/s. How longmust a force of 40.5 N be applied to theball to stop it? 1 s Mass (m) of the ball is m = w / g = (46.5 N) / (9.8m/2) = 4.74 kg Initial speed (u) of the ball = 4.30 m/s Final speed (v) of the ball = 0 Let t be the time taken to come to rest position. Force (F) applied = -40.5 N, here the negative sign indicates thatthe force is applying on the ball in a direction opposite to itsmotion. From the Newton's second law of motion we have F = ma = m(v - u)/t t = m(v - u)/F Substitute all the given values in this formula and do thecalculation work.
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