A uniform electric field exists in the region between twooppositely charged para
ID: 1677210 • Letter: A
Question
A uniform electric field exists in the region between twooppositely charged parallel plates 1.59 cm apart. A proton is released from rest at the surfaceof the positively charged plate and strikes the surface of the opposite plate in a timeinterval 1.57 × 106 s. (i) Find the magnitude of the electricfield. (ii) Find the speed of the proton at the moment itstrikes the negatively charged plate. (iii) Calculate the surface charge density on eachplate. A uniform electric field exists in the region between twooppositely charged parallel plates 1.59 cm apart. A proton is released from rest at the surfaceof the positively charged plate and strikes the surface of the opposite plate in a timeinterval 1.57 × 106 s. (i) Find the magnitude of the electricfield. (ii) Find the speed of the proton at the moment itstrikes the negatively charged plate. (iii) Calculate the surface charge density on eachplate.Explanation / Answer
First find the acceleration of the proton by using basickinematics distance = (1/2) at2 0.0159 = (1/2) a (1.57 x10-6 )2 a = _______ m/s2 q=1.60 x 10-19m=1.67 x10-27
Then you can get the Electric field by using force = ma and force =qE so ma = qE or E = m a / q =___ N/C (this is the E field) And you can get the final speed by using final speed = acc *time = ___ m/s
q=1.60 x 10-19
m=1.67 x10-27
Then you can get the Electric field by using force = ma and force =qE so ma = qE or E = m a / q =___ N/C (this is the E field) And you can get the final speed by using final speed = acc *time = ___ m/s
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