(a) What is the amplitude of the resultantelectric field at point P ? 1 µV/m (b)
ID: 1677640 • Letter: #
Question
(a) What is the amplitude of the resultantelectric field at point P?1 µV/m
(b) What is the ratio of the intensity at point P to theintensity at the center of the interference pattern(IP / Icenter)?
2
(c) Describe where point P is in the interference patternby giving the maximum and minimum between which it lies.
3---Select---central maximum and first minimumfirst minimum and first maximumfirst maximum and second minimumsecond minimum and second maximumsecond maximum and third minimumthird minimum and third maximumthird maximum and fourth minimumfourth minimum and fourth maximum
(d) In a phasor diagram of the electric fields, at what rate wouldthe phasors rotate around the origin?
4 rad/s
(e) In a phasor diagram of the electric fields which pass througheach slit, what is the angle between the phasors?
5°
E1 = (2.00 µV/m) sin[(1.37 1015)t] E2 = (2.00 µV/m) sin[(1.37 1015)t + 10.4 rad]
Explanation / Answer
(a) we can use the phasotr techniques or use thetrig identities here we show that latter approach since sina + sin(a + b) = 2 cos (b / 2) sin (a +b/2) we get that E1 + E2 = 2 Eocos( / 2) sin ( t + ( / 2)) where Eo = 2.00 V / m = 1.37 x 1015 rad / s = 10.4 rad so the electric field amplitude of the resultantwave will be E = 2 Eo cos( / 2) = .......... V / m (b) at point P I = 4 Io(cos(/2))2 = .....Io and at the centre Icen = 4 Io(cos(/2))2
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