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The primary coil of a transformer has 941,137 loops. The secondary coil has 2,83

ID: 1678048 • Letter: T

Question

The primary coil of a transformer has 941,137 loops. The secondary coil has 2,832 loops. The primary coil has a 9 A current and 64 V.

a.) Is this a step-up or step-down transformer? How do you know?Choose one of the following. 1 It is a step-downtransformer because the primary has more loops than thesecondary. It is a step-downtransformer because all transformers are step-downtransformers.     It is astep-up transformer because the primary current isless than the primary voltage. It is astep-up transformer because all transformers arestep-up transformers. It is a step-downtransformer because the primary current is less than the primaryvoltage. It is a step-uptransformer because the primary has more loops than thesecondary.

b.) Determine the power of the primary coil.
2 W
c.) Assuming no losses, determine the power of the secondarycoil.
3 W
d.) Calculate the voltage in the secondary coil.
4 V
e.) Calculate the current in the secondary coil.
5 A
1 It is a step-downtransformer because the primary has more loops than thesecondary. It is a step-downtransformer because all transformers are step-downtransformers.     It is astep-up transformer because the primary current isless than the primary voltage. It is astep-up transformer because all transformers arestep-up transformers. It is a step-downtransformer because the primary current is less than the primaryvoltage. It is a step-uptransformer because the primary has more loops than thesecondary. 1 It is a step-downtransformer because the primary has more loops than thesecondary. It is a step-downtransformer because all transformers are step-downtransformers.     It is astep-up transformer because the primary current isless than the primary voltage. It is astep-up transformer because all transformers arestep-up transformers. It is a step-downtransformer because the primary current is less than the primaryvoltage. It is a step-uptransformer because the primary has more loops than thesecondary. 1

Explanation / Answer

Problem statement: The primary coil of a transformer has941,137 loops. The secondary coil has2,832 loops. The primary coil has a9 A current and 64 V.
(a) Is this a step-up or step-down transformer? How do you know?Choose one of the following. _X_It is a step-downtransformer because the primary has more loops than thesecondary. ___It is astep-down transformer because all transformers arestep-down transformers. ___It is astep-down transformer because all transformers arestep-down transformers. ___It is astep-up transformer because the primary current isless than the primary voltage. ___It is astep-up transformer because all transformers arestep-up transformers. ___It is astep-down transformer because the primary currentis less than the primary voltage. ___It is astep-up transformer because the primary has moreloops than the secondary.
(b) Determine the power of the primary coil.
(c) Assuming no losses, determine the power of the secondarycoil.
(d) Calculate the voltage in the secondary coil.
(e) Calculate the current in the secondary coil.
(b) Determine the power of the primary coil.
(c) Assuming no losses, determine the power of the secondarycoil.
(d) Calculate the voltage in the secondary coil.
(e) Calculate the current in the secondary coil. . 01.   Pprimary = power of the primarycoil = (V)*(I) = (64 volts)*(9 Ampere) = 576 Watts 02.   Psecondary = power of the secondarycoil = (efficiency)*(Pprimary) = (1.0)*(576 Watts) =576 Watts 03.   Vsecondary = (turnsratio)*(Vprimary) = [(2832 loops)/(941137 loops)]*(64volts) = 110.928volts 04.   Isecondary =(Psecondary)/(Vsecondary) = (576Watts)/(110.928 volts) = 5.193 Ampere . . 01.   Pprimary = power of the primarycoil = (V)*(I) = (64 volts)*(9 Ampere) = 576 Watts 02.   Psecondary = power of the secondarycoil = (efficiency)*(Pprimary) = (1.0)*(576 Watts) =576 Watts 03.   Vsecondary = (turnsratio)*(Vprimary) = [(2832 loops)/(941137 loops)]*(64volts) = 110.928volts 04.   Isecondary =(Psecondary)/(Vsecondary) = (576Watts)/(110.928 volts) = 5.193 Ampere .
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