Two sound waves in air (call them X and Y) have wavelengths of1 m and 2 m, andam

Question

Two sound waves in air (call them X and Y) have wavelengths of1 m and 2 m, andamplitudes of 0.03 Pa and 3 Pa, respectively.

a.) Find the frequency of each wave.

fX = 1 Hz
fY = 2 Hz

Which sound wave has a higher pitch: X/Y/neither? b.) Which sound wave is louder: X/Y/neither? Fill in the following:

The intensity of Y is greater than/less than/ the sameas that of X bytimes.

Soundwave Y is dB louder than/softer than/the same loudnessas soundwave X.
(dB=decibels)
Two sound waves in air (call them X and Y) have wavelengths of1 m and 2 m, andamplitudes of 0.03 Pa and 3 Pa, respectively.

a.) Find the frequency of each wave.

fX = 1 Hz
fY = 2 Hz

Which sound wave has a higher pitch: X/Y/neither? b.) Which sound wave is louder: X/Y/neither? Fill in the following:

The intensity of Y is greater than/less than/ the sameas that of X bytimes.

Soundwave Y is dB louder than/softer than/the same loudnessas soundwave X.
(dB=decibels)

Explanation / Answer

x = 1 m, y = 2 m,Ax = 0.03 Pa, Ay = 3 Pa, v = 340 m/s a) fx = v/x = 340 Hz fy = v/y = 170 Hz X has a higher pitch b) intensity I is proportional to f2A2 Iy/Ix =[(fyAy)/(fxAx)]2=(fy/fx)2(Ay/Ax)2= 1002*1/4 = 2.5*103The intensityof Y is greaterthan that of X by 2.5*103 10log(Ix/Iy) = 10log(2.5*103) = 34dB Soundwave Y is 34 dBlouder than soundwaveX

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