Speed of the primary wave V p = 8km/s Travels time of primary wave =t p Speed of

Question

Speed of the primary wave Vp= 8km/s    Travels time of primary wave =tp    Speed of the secondary wave Vs=4.5km/s      Travels time of secondary wave= ts    If d is the distance fromtheearthquake to the seismograph.    Then        ts=d/Vs       tp=d/Vp    The difference in the arrivaltimes is     78s= ts-tp     Therefore     d/4500 m/s - d/8000 m/s= 78s      d = 8.02x 105 m         = 802 km
I don't under how you calculate  d/4500 -d/8000 = 78s to get d = 802km thanks!!! B    Travels time of primary wave =tp    Speed of the secondary wave Vs=4.5km/s      Travels time of secondary wave= ts    If d is the distance fromtheearthquake to the seismograph.    Then        ts=d/Vs       tp=d/Vp    The difference in the arrivaltimes is    The difference in the arrivaltimes is     78s= ts-tp     Therefore     d/4500 m/s - d/8000 m/s= 78s      d = 8.02x 105 m         = 802 km
I don't under how you calculate  d/4500 -d/8000 = 78s to get d = 802km thanks!!! B

Explanation / Answer

   d/4500 - d/8000 = 78s to get         d( 1/4500 - 1/8000)= 78          d = 78 /[1/4500 - 1/8000]           d= 802km

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