The wave function of a plane electromagnetic wave in freespace is: B = 2 X 10 -6

Question

The wave function of a plane electromagnetic wave in freespace is: B = 2 X 10-6 T sin [(3.0 X 104rad/m) x - (9.0 X 1012 rad/s) t]. a.) Find the wave equation for the electric field. b.) Find the intensity of the traveling wave and the directionof the Poynting vector. The wave function of a plane electromagnetic wave in freespace is: B = 2 X 10-6 T sin [(3.0 X 104rad/m) x - (9.0 X 1012 rad/s) t]. a.) Find the wave equation for the electric field. b.) Find the intensity of the traveling wave and the directionof the Poynting vector.

Explanation / Answer

The wave function of a plane electromagnetic wave in freespace is B = 2 X 10-6 T sin [(3.0 X 104rad/m) x - (9.0 X 1012 rad/s) t]. a.) the wave equation for the electric field E = Eo sin [(3.0X 104 rad/m) x - (9.0 X 1012 rad/s) t] where Eo = amplitud eof electric field = Bo * c          Bo =amplitud eof magnetic field = 2 * 10 ^ -6 T            c = speed of EM wave = 3* 10 ^ 8 m / s plug the values we get Eo = 600 V / m Therefore the wave equation for the electric field E= (600V /m) sin [(3.0 X 104 rad/m) x - (9.0 X1012 rad/s) t] b.) the intensity of the traveling wave S= cBo^ 2 / where = 4* 10 ^ -7 H/ m Plug the values we get S = 954.92 W /m^ 2 the direction of the Poynting vector is perpendicular to bothelectric and magnetic fields

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