\"Particle A and particle B are held together with a compressedspring between th
ID: 1678964 • Letter: #
Question
"Particle A and particle B are held together with a compressedspring between them. When they are released, the springpushes them apart, and they then fly off in opposite directions,free of the spring. The mass of A is 5.2 times of B, andthe energy stored in the spring was 29J. Assume thatthe spring has negligble mass and that all its stored energy istransferred to the particles. Once that transfer is complete,what are the kinetic energies of: #1) particle A and #2) particle B " Thank you! "Particle A and particle B are held together with a compressedspring between them. When they are released, the springpushes them apart, and they then fly off in opposite directions,free of the spring. The mass of A is 5.2 times of B, andthe energy stored in the spring was 29J. Assume thatthe spring has negligble mass and that all its stored energy istransferred to the particles. Once that transfer is complete,what are the kinetic energies of: #1) particle A and #2) particle B " Thank you!Explanation / Answer
Given mA = 5.2 mB ---( 1) energy stored in the spring E = 29 J from law of conservation of momentum mAvA = mBvB vA = ( mB / mA ) * vB = ( 1/ 5.2 )vB Since from eq ( 1) vB= 5.2 vA -----( 2) Kinetic energy of A + kinetic energy of B = 29 J ( 1/ 2) mA * vA^ 2 + ( 1/ 2) mB* vB^ 2 = 29 J ( 1/ 2) mA * vA ^ 2 + [ ( 1/ 2) ( mA) *5.2 *vA ^ 2 ] =29 J 6.2 * ( 1/ 2) mA * vA ^ 2 = 29 J from this kinetic energy of A is ( 1/ 2) mA * vA ^ 2 =29 J / 6.2 =4.677 J (2) kinetic energy of B is = ( 1/ 2) mB * vB ^ 2 =29 J - 4.677 J = 24.32 JRelated Questions
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