What battery voltage is necessary to supply 0.50 A of currentto a circuit with a

Question

What battery voltage is necessary to supply 0.50 A of currentto a circuit with a resistance of 29 ? ______volts Two resistors with values of 21 and 39,respectively, are connected in parallel and hooked to a 10 Vbattery. a) What would be the current in the circuit? ___A b) What would be the power expanded in the circuit?_____W An object has nine million more electrons than protons. Whatis the net charge of the object? ___C What battery voltage is necessary to supply 0.50 A of currentto a circuit with a resistance of 29 ? ______volts Two resistors with values of 21 and 39,respectively, are connected in parallel and hooked to a 10 Vbattery. a) What would be the current in the circuit? ___A b) What would be the power expanded in the circuit?_____W An object has nine million more electrons than protons. Whatis the net charge of the object? ___C

Explanation / Answer

V=I*R = 0.5A*29 = 14.5V What battery voltage is necessary to supply 0.50 A of currentto a circuit with a resistance of 29 ? answer: 14.5V Two resistors with values of 21 and 39,respectively, are connected in parallel and hooked to a 10 Vbattery. a) What would be the current in the circuit? ___A Req = 21*39/(21+39) =13.65 I = V/Req = 10V/13.65 = 0.73A current is 0.73A b) What would be the power expanded in the circuit? Power P = IV = 0.73A*10V = 7.3W An object has nine million more electrons than protons. Whatis the net charge of the object? the net charge will be Q = 9 million* (-e) =9000000*(-1.6*10-19 C) = -1.44*10-12 C Two resistors with values of 21 and 39,respectively, are connected in parallel and hooked to a 10 Vbattery. a) What would be the current in the circuit? ___A Req = 21*39/(21+39) =13.65 I = V/Req = 10V/13.65 = 0.73A current is 0.73A b) What would be the power expanded in the circuit? Power P = IV = 0.73A*10V = 7.3W An object has nine million more electrons than protons. Whatis the net charge of the object? the net charge will be Q = 9 million* (-e) =9000000*(-1.6*10-19 C) = -1.44*10-12 C

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