Three capacitors (1.4µF, 3.0 µF, 5.8 µF) are connected in series to an ac voltag

Question

Three capacitors (1.4µF, 3.0 µF, 5.8 µF) are connected in series to an ac voltagesource with amplitude 12.0 V and frequency6.1 kHz. (a) What are the peak voltages across eachcapacitor?
V1.4µF =1 V
V3.0µF =2 V
V5.8µF =3 V

(b) What is the peak current that flows in the circuit?
4 A
Three capacitors (1.4µF, 3.0 µF, 5.8 µF) are connected in series to an ac voltagesource with amplitude 12.0 V and frequency6.1 kHz. (a) What are the peak voltages across eachcapacitor?
V1.4µF =1 V
V3.0µF =2 V
V5.8µF =3 V

(b) What is the peak current that flows in the circuit?
4 A
(a) What are the peak voltages across eachcapacitor?
V1.4µF =1 V
V3.0µF =2 V
V5.8µF =3 V

(b) What is the peak current that flows in the circuit?
4 A 26. –/1points Notes Question: GRRPhys121.P.024. Question part Points Submissions 1 0/1 0/5 Total 0/1 At what frequency is the reactance of a20.0 mH inductor equal to 24.5 ?
1 Hz
26. –/1points Notes Question: GRRPhys121.P.024. 26. –/1points Notes Question: GRRPhys121.P.024. Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions Question part Points Submissions 1 0/1 0/5 Total 0/1 Total 0/1 At what frequency is the reactance of a20.0 mH inductor equal to 24.5 ?
1 Hz
At what frequency is the reactance of a20.0 mH inductor equal to 24.5 ?
1 Hz
27. –/1points Notes Question: GRRPhys121.P.025. 27. –/1points Notes Question: GRRPhys121.P.025. Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions 1 0/1 0/5 Total 0/1 Question part Points Submissions Question part Points Submissions 1 0/1 0/5 Total 0/1 Total 0/1 1 0/1 0/5

Explanation / Answer

Reactance of : X1(1.4) = 1/C1 = 18.636 X2(3) = 1/C2 = 8.697 X3(5.8) = 1/C3 = 4.498 => the peak current : I = V/(X1+ X2 + X3) =0.377 A => the peak voltage : V1 = I*X1 = 7.0256 V V2 = I*X2 = 3.2787 V V3 = I*X3 = 1.6957 V

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