One mole of oxygen gas is at a pressure of 5.60 atm and a temperatureof 26.0°C.

Question

One mole of oxygen gas is at a pressure of 5.60 atm and a temperatureof 26.0°C. (a) If the gas is heated at constant volume until the pressuretriples, what is the final temperature?
°C

(b) If the gas is heated so that both the pressure and volume aredoubled, what is the final temperature?
°C
(a) If the gas is heated at constant volume until the pressuretriples, what is the final temperature?
°C

(b) If the gas is heated so that both the pressure and volume aredoubled, what is the final temperature?
°C

Explanation / Answer

t1 = 26 P2 = 3P1 = 3(5.6) = 16.8 atm
a) P1 / P2 = t1 / t2
t2 = P2 / P1 * t1    = (16.8)(5.6) * 26 = 78 C
b) P1V1 / t1 =P2V2 / t2
P1V1 / t1 =4P1V1 / t2
1 / t1 = 4 /t2 t2 = 4t1 =4(26) = 104 C

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