A 65kg skier is moving at 6050 m/s on a frictionless,horizontal snow-covered pla
ID: 1680884 • Letter: A
Question
A 65kg skier is moving at 6050 m/s on a frictionless,horizontal snow-covered plateau when she encounters a rough patch3.50m long. The coefficient at kinetic friction between thsi patchand her skis is 0.300. After crossing the rough patch and returningto friction-free snow, she skis down an icy frictionless hill 2.50mhigh, a) How far the skier moving when she gets the bottom of thehill? b) How much internal enrgy was generated in crossing the roughpatch? A 65kg skier is moving at 6050 m/s on a frictionless,horizontal snow-covered plateau when she encounters a rough patch3.50m long. The coefficient at kinetic friction between thsi patchand her skis is 0.300. After crossing the rough patch and returningto friction-free snow, she skis down an icy frictionless hill 2.50mhigh, a) How far the skier moving when she gets the bottom of thehill? b) How much internal enrgy was generated in crossing the roughpatch?Explanation / Answer
mass m = 65 kg velocity v = 6050 m / s length of rough patch L = 3.5 m The coefficient at kinetic friction between thsi patch and herskis = 0.300 Height h = 2.50m Accleration on rough patch a = -g = -2.94 m / s^ 2 velocity of the skier after passing through rough patch V =? from the relation V ^ 2 - v^2 = 2aL V = [ v ^ 2 + 2aL ] ~6050 m / s internal enrgy was generated in crossing the rough patch =work done on rough patch = frictional force * length of the rough patch = mg * L = 668.85 JRelated Questions
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