Q#2 A particle of charge 2.5*10upper -6 C is moving at 500m/sec in a direction 3
ID: 1680954 • Letter: Q
Question
Q#2 A particle of charge 2.5*10upper -6 C is moving at 500m/sec in a direction 30 deg N of E . At the location of theparticle, the magnetic field has size 0.4 T . The particle isexperiencing an instantanoues magnetic force (due to thisfield) of 1.71*10upper -4 newtons directed vertically down. Thesize of the angle A (in deg) between the velocity and the magneticfield at thelocation of the particle is mostly nearly( ) (a)0 (b)12.6 (c)15.9 (d)17.1 (e)20.0 (a,b)24.1 (a,c)28.3 (a,d)70 Q#2 A particle of charge 2.5*10upper -6 C is moving at 500m/sec in a direction 30 deg N of E . At the location of theparticle, the magnetic field has size 0.4 T . The particle isexperiencing an instantanoues magnetic force (due to thisfield) of 1.71*10upper -4 newtons directed vertically down. Thesize of the angle A (in deg) between the velocity and the magneticfield at thelocation of the particle is mostly nearly( ) (a)0 (b)12.6 (c)15.9 (d)17.1 (e)20.0 (a,b)24.1 (a,c)28.3 (a,d)70Explanation / Answer
F = q v x B = q v B sin sin = 1.71 * 10E-4 / (2.5 * 10E-6 * 500 * .4) =.342 = 20 degRelated Questions
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