A rubber ball (mass 0.23 kg) is droppedfrom a height of 1.7 m onto the floor.Jus

Question

A rubber ball (mass 0.23 kg) is droppedfrom a height of 1.7 m onto the floor.Just after bouncing from the floor, the ball has a speed of3.9 m/s. (a) What is the magnitude and direction of theimpulse imparted by the floor to the ball? Magnitude 1 kg · m/s Direction 2---Select---downwardupwardclockwiseradially outwardradially inward
(b) If the average force of the floor on the ball is 20 N, how long is the ball in contact with thefloor?
3 s (a) What is the magnitude and direction of theimpulse imparted by the floor to the ball? Magnitude 1 kg · m/s Direction 2---Select---downwardupwardclockwiseradially outwardradially inward
(b) If the average force of the floor on the ball is 20 N, how long is the ball in contact with thefloor?
3 s Magnitude 1 kg · m/s Direction 2---Select---downwardupwardclockwiseradially outwardradially inward

Explanation / Answer

           Mass (m) = 0.23 kg               Initial velocity (v1) = 2gh                                              = 2*9.8*1.7 = 5.77 m /s               final velocity (v2) = 3.9 m /s (a)      we know that ,             Impulse   J = m (v2 - v1)                               = 0.23 ( 3.9 - 5.77)                               = - 0.4306 kg . m /s Direction is upwards. (b)         we knowthat                           F.t = J                        t = J / F                                 =   0.4306 / 20 = 0.0215 s

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