A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed

Question

A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed so that the normal to its plane makes an angleof 50.9° with a uniform magnetic field of magnitude 15.0 T.(a) Calculate the magnitude of the magnetic dipolemoment of the loop in amperes-square meters. (b)What is the magnitude of the torque acting on the loop? Thanks for the help A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed so that the normal to its plane makes an angleof 50.9° with a uniform magnetic field of magnitude 15.0 T.(a) Calculate the magnitude of the magnetic dipolemoment of the loop in amperes-square meters. (b)What is the magnitude of the torque acting on the loop? Thanks for the help

Explanation / Answer

a) Given that Radius(r) of the circular loop = 0.149m Current(I) = 3.04 A Angle() = 50.9o Magnetic field strength(B) = 15.0T Now formula for calculating the value of the magnetic dipolemoment of the loop is                M = IA                    = Ir2                    = (3.04A)(3.14)(0.149m)2 b) Formula for calculating the value of the torque acting ontheloop is '                = BIAsin                  =BIr2sin

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