Two cars travel along a straight road. When astopwatch reads t = 0.00 h, car A i

Question

Two cars travel along a straight road. When astopwatch reads t = 0.00 h, car A is atdA = 48.0 km moving at a constant 35.0 km/h. Later, when the watch reads t =0.50 h, car B is at dB = 0.00 km moving at51.0 km/hr. Answer the followingquestions, first, graphically by creating a position-time graph,and second, algebraically by writing down equations for thepositions dA and dB as afunction of the stopwatch time, t. (a) What will the watch read when car B passescar A? (b) At what position will car B pass carA? (c) When the cars pass, how long will it havebeen since car A was at the reference point? I have solved this problem a fewtimes and each time it has been wrong. The first answer that I knewwas wrong was;    (a)3.5  hr     (b) 153km    (c) 4 hr The second one, and one that Ithought was right, I put; (a) 9.75 h    (b) 389.25 km   (and didnt bother doing part cbecause the first two were wrong
Two cars travel along a straight road. When astopwatch reads t = 0.00 h, car A is atdA = 48.0 km moving at a constant 35.0 km/h. Later, when the watch reads t =0.50 h, car B is at dB = 0.00 km moving at51.0 km/hr. Answer the followingquestions, first, graphically by creating a position-time graph,and second, algebraically by writing down equations for thepositions dA and dB as afunction of the stopwatch time, t. (a) What will the watch read when car B passescar A? (b) At what position will car B pass carA? (c) When the cars pass, how long will it havebeen since car A was at the reference point? I have solved this problem a fewtimes and each time it has been wrong. The first answer that I knewwas wrong was;    (a)3.5  hr     (b) 153km    (c) 4 hr The second one, and one that Ithought was right, I put; (a) 9.75 h    (b) 389.25 km   (and didnt bother doing part cbecause the first two were wrong
The second one, and one that Ithought was right, I put; (a) 9.75 h    (b) 389.25 km   (and didnt bother doing part cbecause the first two were wrong

Explanation / Answer

equations car a   da = 35t + 48   car b   0 = 51(.5) +g        g= -25.5       db = 51t - 25.5        a) set the equations equal to eachother            35t + 48  = 51t - 25.5 16t = 73.5 t = 4.59h b) t = 4.59    da = 35t + 48 =208.78 km c) the way it is phrase it is the same answer as partA       t = 4.59h

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