The figure shows a lower leg being exercised. It has a 49-Nweight attached to th

Question

The figure shows a lower leg being exercised. It has a 49-Nweight attached to the foot and is extended at an angle withrespect to the vertical. Consider a rotational axis at the knee, asindicated. (a) When angle = 49°, find themagnitude of the torque that the weight creates.(b) At what angle does the magnitude of the torquehave a value of 11 N·m? The figure shows a lower leg being exercised. It has a 49-Nweight attached to the foot and is extended at an angle withrespect to the vertical. Consider a rotational axis at the knee, asindicated. (a) When angle = 49 Degree , find themagnitude of the torque that the weight creates.(b) At what angle does the magnitude of the torquehave a value of 11 Nm?

Explanation / Answer

a) We first need to calculate the perpendicular distance from theweight to the equilibrium line (the original, vertical line). Thedistance is       r = 0.55 * sin49 = 0.415m Now the torque is = 0.415m x 49N = 20.33Nm b) We need to solve for such that:              0.55sin() x 49 = 11 ==>       sin() = 11/(49x0.55)                                      = 0.4081.    Therefore = 24.08degrees

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