One strategy in a snowball fight is to throw a snowball at a high angle over lev
ID: 1683082 • Letter: O
Question
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching that snowball, you throw a second one at a low angle timed to arrive before or at the same time as the first one. Assume that both snowballs are thrown with a speed of 30.0 m/s. The first one is thrown at an angle of 70.0° with respect to the horizontal.(a) At what angle should the second snowball be thrown to arrive at the same point as the first?
Degrees
(b) How many seconds later should the second snowball be thrown after the first in order for both to arrive at the same time?
seconds
Explanation / Answer
The formula to be used is projectile motion. As a matter of fact, remember that the 2 angles at which projectiles reach the same point, are complementary, i.e. their sum is 90 degrees. You can confirm this by looking into the your textbook for the formula for range [it probably is v^2 sin 2A / 2 g] and recalling that sin (90 - A) = cos A, cos (90 - A) = sin A; so sin 2A = sin 2(90-A) [using the formula sin2X=2sinXcosX]. Thus the answer to your first question is 20 degrees. Time of Flight is given by 2 v sinA / g. Put the values v = 30, A = 70 degrees, g = 9.8m/s^2 and get the answer!
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