18) A 3.7 pC charge experiences a force of 8.1 X 10^-7 N in an electric field. F

Question

18) A 3.7 pC charge experiences a force of 8.1 X 10^-7 N in an electric field. Find the electric field.


19) Two charges are located on the x-axis. A 22 C charge is located at the origin and a 47 C charge is located at x = 4.0 m. What is the magnitude of the electric field at
x = 7.5 m ? 18) A 3.7 pC charge experiences a force of 8.1 X 10^-7 N in an electric field. Find the electric field.


19) Two charges are located on the x-axis. A 22 C charge is located at the origin and a 47 C charge is located at x = 4.0 m. What is the magnitude of the electric field at
x = 7.5 m ?

Explanation / Answer

18) A 3.7 pC charge experiences a force of 8.1 X 10^-7 N in an electric field. Find the electric field. E=F/qo E=(8.1x10^-7N)/(3.7x10^-12C)=218918.9N/C 19) Two charges are located on the x-axis. A 22 µC charge is located at the origin and a 47 µC charge is located at x = 4.0 m. What is the magnitude of the electric field at x = 7.5 m ? Use E=kq1/r^2 to determine the individual fields at 7.5m: E1=((9x10^9)(22x10^-6))/(7.5^2)=.352N/C E2=((9x10^9)(47x10^-6))/(3.5^2)=34530.6N/C To find the net electric field at 7.5m, add these two quantities: .352N/C+34530.6N/C=34531N/C net field at 7.5m.

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