A 62 resistor is connected in series with a 93 mH inductor and a 0.2 F capacitor

Question

A 62 resistor is connected in series with a 93 mH inductor and a 0.2 F capacitor. The applied voltage has the form E = 190 V sin(2 f t), where the frequency is f = 1178 cycles/s. Find the rms current. Answer in units of A.

I have tried this probs several ways inclduing: V=IXL for prob 15. I believe my prob is that the supposed "applied voltage has the form E = 190 V sin(2 pi f t)" I need to solve for E(which I will plug in for V) but I am unsure of what "t" is suppose to be. Please help. Thanks
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015 (part 2 of 4) 6.0 points
Find the rms voltage across R.
Answer in units of V.
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016 (part 3 of 4) 5.0 points
Find the rms voltage across L.
Answer in units of V.
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017 (part 4 of 4) 5.0 points
Find the rms voltage across C.
Answer in units of V.

Explanation / Answer

The resistor in the circuit is R = 62 The inductor in the circuit is L = 93 mH = 93 * 10-3 H The capacitor in the circuit is C = 0.2 F = 0.2 * 10-6 F The inductor in the circuit is L = 93 mH = 93 * 10-3 H The applied voltage has the form E = 190 V sin(2 f t), where the frequency is f = 1178 cycles/s. The total impedance of the circuit is Z = [R2 + (wL - 1/wC)2]1/2 where w = 2f,f = 1178 cycles/s The maximum current in the circuit is Io = (Eo/Z) or Io = (Eo/[R2 + (wL - 1/wC)2]1/2) The rms current in the circuit is Irms = (Io/2) or Irms = ((Eo/2 * [R2 + (wL - 1/wC)2]1/2) where w = 2f,f = 1178 cycles/s The maximum current in the circuit is Io = (Eo/Z) or Io = (Eo/[R2 + (wL - 1/wC)2]1/2) The rms current in the circuit is Irms = (Io/2) or Irms = ((Eo/2 * [R2 + (wL - 1/wC)2]1/2)

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