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A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This paralle

ID: 2136371 • Letter: A

Question

A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This parallel group is connected in series with a 29.3-? resistor. The total combination is connected across a 16.4-V battery. Find (a) the current and (b) the power dissipated in the 131.7-? resistor.

A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This parallel group is connected in series with a 29.3-? resistor. The total combination is connected across a 16.4-V battery. Find (a) the current and (b) the power dissipated in the 131.7-? resistor.

Explanation / Answer

net R = 29.3 + ( 60.3*131.7/60.3+131.7) = 70.36 ohms

i = 16.4/70.36 = 0.233 amp

power dissipated = V*V /r = 0.69585 watts

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