A 75.7kg man steps off a platform 3.09m above the ground. He keeps his legs stra

Question

A 75.7kg man steps off a platform 3.09m above the ground. He keeps his legs straight as he falls, but at the moment his feet touch the ground his knees begin to bend, and, treated as a particle, he moves an additional 0.650m before coming to rest.

-What is his speed at the instant his feet touch the ground?

-Treating him as a particle, what is the magnitude of his acceleration as he slows down if the acceleration is constant?

-Treating him as a particle, what is the direction of his acceleration as he slows down if the acceleration is constant?

-Draw a free-body diagram of this man as he is slowing down.

-Use Newton's laws and the results of part B to calculate the force the ground exerts on him while he is slowing down. Express this force in newtons.

-Use Newton's laws and the results of part to calculate the force the ground exerts on him while he is slowing down. Express this force as a multiple of the man's weight.

-What is the magnitude of the reaction force to the force you found in part E?

-What is the direction of the reaction force to the force you found in part E?

Explanation / Answer

As the platform is above the ground h = 3.09m and assumng that he is on surface of earth...
mgh = v = =7.7822m/s

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