Find the sum of these four vector forces: 10.5 N to the right at 35.0° above the

Question

Find the sum of these four vector forces: 10.5 N to the right at 35.0° above the horizontal, 31.0 N to the left at 54.5° above the horizontal, 8.60 N to the left at 35.0° below the horizontal, and 24.0 N to the right at 50.0° below the horizontal. (Hint: N stands for newton, the SI unit of force. The component method allows the addition of any vectors - forces as well as displacements and velocities. Make a drawing of this situation, and select the best axes for x and y so that you have the least number of components.)
.....N at .......° counterclockwise from the horizontal line to the right

Explanation / Answer

A = 10.5 N to the right at 35.0° above the horizontal, B = 31.0 N to the left at 54.5° above the horizontal, C = 8.60 N to the left at 35.0° below the horizontal, D = 24.0 N to the right at 50.0° below the horizontal. find their sum S Ax = 10.5cos(35.0), Ay = 10.5sin(35.0) Bx = -31.0cos(54.5), By = 31.0sin(54.5) Cx = -8.60cos(35.0), Cy = -8.60sin(35.0) Dx = 24.0cos(50.0), Dy = -24.0sin(50.0) Sx = Ax + Bx + Cx + Dx = -1.0185 N Sy = Ay + By + Cy + Dy = 7.9423 N so S = 8.01 N angle = arctan(7.9423/1.0185) = 82.7° below the horizontal. answer: 8.01 N to the left at 82.7° above the horizontal.

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.