a 45g block of copper at -12 degrees celcius is added to 110g of water in a 75g
ID: 1685113 • Letter: A
Question
a 45g block of copper at -12 degrees celcius is added to 110g of water in a 75g aluminium cup. the cup and the water have an initial temperature of 4.1degrees celcius a) find the equilibirium temperature of the cup and its contents determine the mass of ice if any is present when the system reaches equilibirum. a 45g block of copper at -12 degrees celcius is added to 110g of water in a 75g aluminium cup. the cup and the water have an initial temperature of 4.1degrees celcius a) find the equilibirium temperature of the cup and its contents determine the mass of ice if any is present when the system reaches equilibirum.Explanation / Answer
mass of the copper block is m_c = 45 g = 0.045 kg Temperature of the copper block is T_c = -12 C mass of the Aluminium cup is m _Al = 75 g = 0.075 kg mass of the water is m_w = 110 g = 0.11 kg Initial temperature is T _i = 4.1 C m_w c_w + m_Al c_Al ) ( 4.1 C - T ) = m_c * Cu_c ( T - ( -12 C ) 0.11 kg * 4186 J / kg * C + 0.075 kg * 920 J / kg C ( 4.1 - T ) = 0.045 kg * 390J /kg C ( T + 12 C ) solving for the Temperature T = 3.5 C mass of the copper block is m_c = 45 g = 0.045 kg Temperature of the copper block is T_c = -12 C mass of the Aluminium cup is m _Al = 75 g = 0.075 kg mass of the water is m_w = 110 g = 0.11 kg Initial temperature is T _i = 4.1 C m_w c_w + m_Al c_Al ) ( 4.1 C - T ) = m_c * Cu_c ( T - ( -12 C ) 0.11 kg * 4186 J / kg * C + 0.075 kg * 920 J / kg C ( 4.1 - T ) = 0.045 kg * 390J /kg C ( T + 12 C ) solving for the Temperature T = 3.5 CRelated Questions
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