Now imagine that there is a similar set of photodiodes, also spaced 1.00 m apart

Question

Now imagine that there is a similar set of photodiodes, also spaced 1.00 m apart along a north-south axis, mounted on a dock on shore directly ahead of the aircraft carrier. The light from the flashlight on the pool table encounters these two photodiodes. What is the time tdock that elapses between when the flash of light encounters the first photodiode and when it strikes the second?

Express your answer in seconds to nine significant figures. Remember that an answer such as 1/300000025 will be accepted at its calculated value (if you do not put commas in your answer). Use c = 299,792,458; { m m/s} for the speed of light in vacuum.

Explanation / Answer

Event 1 is when a flash of light from a light source leaves O'.Event 2 is when the flash returns to O',having been reflected from the two photodiodes spaced a distance d = 1.00 m away.We label the time interval ?to,using the subscript zero as a remainder that the apparatus is at rest,with zero velocity,in frame S'.The flash of light moves a total distance 2d,so the time interval is
?to = (2d/c) where c = 299,792,458 m/s is the speed of light in vacuum.

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.