10) In the reaction ^4 He + ^9 Be ----> n + ^12 C how much energy is released or

Question

10) In the reaction ^4 He + ^9 Be ----> n + ^12 C how much energy is released or absorbed ? The mass of ^4 He is 4.0026032 u, the mass of ^9 Be is 9.0121821 u, the mass of n is 1.0086649 u, and the mass of ^12 C is 12.0000000 u.


ANS: 5.70 MeV released

Explanation / Answer

Give reaction ^4 He + ^9 Be ----> n + ^12 C and The mass of ^4 He m = 4.0026032 u the mass of ^9 Be m ' = 9.0121821 u the mass of n m " = 1.0086649 u the mass of ^12 C is m "' = 12.0000000 u. mass defect dm = ( m+ m' ) -(m" + m"') = 0.0061204 u This is positive .So, energy released Therefore energy released dE = dm*931.5 MeV = 5.7011 MeV

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